Hints:

i. Iterate each input words(map/dictionary) against given string (nested loop), to find index of each word.

ii. Save frequency of each word in another map to check the exact no of matches only.

Code & Explanation added along with comments:

Time Complexity: O(m*n) , m — no of words, n — string range with total word chars.

Space Complexity:

O(m*n + k), k — result list.

Please comment your queries or thoughts.

Thanks for your read and claps 👏 👏👏

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Tirupati Rao (bitbee)
Tirupati Rao (bitbee)

Written by Tirupati Rao (bitbee)

Technical Writing | YT ▶️ BitBee | #Tech #Coding #interviews #bitbee #datastructures #algorithms #leetcode

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